Mrs. James Christie: Difference between revisions

Latest revision as of 20:05, 16 December 2016

Mrs. James Christie Click on the tune title to see or modify Mrs. James Christie's annotations. If the link is red you can create them using the form provided.Browse Properties <br/>Special:Browse/:Mrs. James Christie Query the Archive
Theme code Index	115L3L 1566
Also known as
Composer/Core Source	J. Scott Skinner
Region	Scotland
Genre/Style	Scottish
Meter/Rhythm	Strathspey
Key/Tonic of	B
Accidental	2 flats
Mode	Ionian (Major)
Time signature	4/4
History
Structure	AB
Editor/Compiler	J. Scott Skinner
Book/Manuscript title	Book:Cairngorum Collection Part 3
Tune and/or Page number
Year of publication/Date of MS	192?
Artist
Title of recording
Record label/Catalogue nr.
Year recorded
Media
Score ()

X:1
T:Mrs. James Christie
M:C
L:1/8
R:Strathspey
C:J. Scott Skinner
K:Bb
F|B>AB<d F<BD<F|B>df>^f g3=f|e>dc>=B c<e G<_B|
A>cf>=e (3gf_e (3dec|B>AB<d F<B D<F|B>df>^f g3=f|e>dc>=B c<eG<_B|
A<c F>A B2 B||F|B>df>_a g<e ez|c>=eg>b a<f f2|
B>df>_a g<b e>g|f<de>c d<B B>F|B/c/d/e/ f>_a g<e ez|
c/d/=e/f/ g>b a<f f^f|(3g^fg (3bge (3=f=ef (3bfd|ec/B/ A/c/f d<B B||

Tune annotations

@@ Line 1: / Line 1: @@
 {{Abctune
 |f_tune_title=Mrs. James Christie
-|f_composer=Biography:J. Scott Skinner,
+|f_composer=J. Scott Skinner,
 |f_country=Scotland
 |f_genre=Scottish
@@ Line 10: / Line 10: @@
 |f_mode=Ionian (Major)
 |f_structure=AB
-|f_book_title=The Beauties of the North
+|f_book_title=Cairngorum Collection Part 3
-|f_collector=Bill Hardie
+|f_collector=J. Scott Skinner
-|f_year=1986
+|f_year=192?
-|f_page=p. 38
 |f_theme_code_index=115L3L 1566
 }}
@@ Line 19: / Line 18: @@
 ----
 <pre>
-X:0
+X:1
-T: No Score
+T:Mrs. James Christie
-C: The Traditional Tune Archive
+M:C
-M:
+L:1/8
-K:
+R:Strathspey
-x
+C:J. Scott Skinner
+K:Bb
+F|B>AB<d F<BD<F|B>df>^f g3=f|e>dc>=B c<e G<_B|
+A>cf>=e (3gf_e (3dec|B>AB<d F<B D<F|B>df>^f g3=f|e>dc>=B c<eG<_B|
+A<c F>A B2 B||F|B>df>_a g<e ez|c>=eg>b a<f f2|
+B>df>_a g<b e>g|f<de>c d<B B>F|B/c/d/e/ f>_a g<e ez|
+c/d/=e/f/ g>b a<f f^f|(3g^fg (3bge (3=f=ef (3bfd|ec/B/ A/c/f d<B B||
 </pre>
 ----