Polonaise (2): Difference between revisions

Find traditional instrumental music
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T:Polonaise [2]
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d3 (bag)|^g2 a2 z2|a(a/g/) f(f/e/) d(d/c/)| (c/B/e/d/) dBc^d|
d3 (bag)|^g2 a2 z2|a(a/g/) f(f/e/) d(d/c/)| (c/B/e/d/) dBc^d|
d^c dB=cd|e g2 (a/g/) .f/.e/.d/.c/|Bc^cd d/=c/A/F/|A4 G2!D.C.!:|]
d^c dB=cd|e g2 (a/g/) .f/.e/.d/.c/|Bc^cd d/=c/A/F/|A4 G2!D.C.!:|]
 
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Latest revision as of 19:32, 21 February 2024


Polonaise (2)  Click on the tune title to see or modify Polonaise (2)'s annotations. If the link is red you can create them using the form provided.Browse Properties <br/>Special:Browse/:Polonaise (2)
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 Theme code Index    551H 2H3H0
 Also known as    
 Composer/Core Source    
 Region    England
 Genre/Style    English
 Meter/Rhythm    Country Dance
 Key/Tonic of    D
 Accidental    2 sharps
 Mode    Ionian (Major)
 Time signature    3/4
 History    
 Structure    AABBCC
 Editor/Compiler    Biography:James Manson
 Book/Manuscript title    Book:Hamilton's Universal Tune Book vol. 2
 Tune and/or Page number    p. 32
 Year of publication/Date of MS    1846
 Artist    
 Title of recording    
 Record label/Catalogue nr.    
 Year recorded    
 Media    
 Score   (1)   




X:1 T:Polonaise [2] M:3/4 L:1/8 C:J. Kuffner B:Manson – Hamilton’s Universal Tune Book, vol. 2 (1846, p. 32) Z:AK/Fiddler’s Companion K:D A3 (B/c/) de|(^e2f) z z2|f3=e {e}d/c/d/B/|(^G2A) z z2|(A3 gfe)| {e}(d/c/d/e/ f)(Adf)|e2 e/a/^g/f/ e/d/B/^G/|(B4 A2):| |:AA/A/ Aacd|ef gg/e/ c/A/=G/E/|D/F/A/d/ (f2 e/f/g/e/)|(d4 c2)| AA/A/ AAcd|ef gg/e/ c/A/G/E/|D/F/A/d/ (f2 e/d/c/B/)|A2 z (e^de)| (f3e) (e/=d/c/B/)|(A/B/c/d/) e(e^de)|(f3e) e/=d/c/B/|A2 z (A/^G/ A/B/c/d/)| e2 zc/B/ (c/d/e/f)|g2 z(.g.g.g)|(g>e/2c/4) A/z/ (.g.g.g)|g>e/2c/4 z/(.g.g.g)| g3e c/A/G/E/|!fermata!C6|(A3 B/c/) de|^e2f z z2|(f3=e) {e}d/c/d/B/|(^G2A)z z2| (A3 gfe)|{e}(d/c/d/e/ f)(Adf)|a3f {f}e/d/e/f/|d(3D/F/A/ d(3F/A/d/ f(3A/d/f/|(g/>f/)(e/>d/) (c/>B/)(A/>G/) (F/>E/)(D/>C/)| D(3D/F/A/ d(3F/A/d/ f(3A/d/f/|(g/>f/)(e/>d/) (c/>B/)(A/>G/) (F/>E/)(D/>C/)|D(3D/F/A/ d(3D/F/A/ d(3D/F/A/|d>D D2!fine!z2:| K:G d3 (bag)|^g2 a2 z2|a(a/g/) f(f/e/) d(d/c/)| (c/B/e/d/) dBc^d| d^c dB=cd|e g2 (a/g/) .f/.e/.d/.c/|Bc^cd d/=c/A/F/|A4 G2!D.C.!:|]