Annotation:Reel (153)
X:1 T:Untitled T:Reel [153] M:C| L:1/8 N:Compare with "Jenny's Welcome to Charlie" N:From an August 24, 1966, field recording of the playing of Fidel N:Martin (1891-1976) of Berlin N.H., originally from Rogersville, NB, recorded N:by folklorist Art Rosenbaum. Martin, a WWI veteran, had a repertory that N:consisted of Acadian, Irish, American and French-Canadian tunes. D:https://bmac.libs.uga.edu/index.php/Detail/objects/331506 F:UGA Brown Media Archives: identifier artrosen_0056 (Track 18 -05:20 the tape) Z:Transcribed by Andrew Kuntz K:Dmix P:A AdAd dedc|AccB cdcB|Addc ddAB |cAG(E {F}E)D D2| AdAd dedc|AccB cdcB|Addc defg|ageg fd d2|| P:B d>efg abag|ecgc ac{ga}gc|defg abag|ecee (e/4f/4e/)ddd| defg a2 ag|ecgc ac{ga}gc|defg abag|eceg fdd2|| P:A' [M:5/4]Addc ded2 Ad| [M:C|] cBcd cBAd|Addc d2 Ad|cAG(E {F}E)D D2| AdAd dedc|ABcB cdcB|Addc ddfg|a2eg fd[df]d|| P:B' defg aba2|ecgc ac{ga}gc|defg abag| eceg fdAd| defg abag|ecgc ac{ga}gc|defg abaa|eceg fd [d2f2]||
REEL [153]. American? Canadian? Irish?, Reel (cut time). D Mixolydian. Standard tuning (fiddle). AB. This untitled reel of unknown provenance was played by fiddler biography:Fidel Martin (1891-1976) of Berlin, New Hampshire, and recorded in the field in 1966 by folklorist Art Rosenbaum. Martin was originally from Rogersville, New Brunswick, but lived most of his life in Berlin. He is buried in Colebrook, New Hampshire. He had an eclectic repertory of Acadian, Quebecois, American and Irish tunes, but at the core seems to have been an Acadian player who kept up a constant podorhythmie (percussive foot-tapping) no matter what genre he played. This untitled reel should be compared with "Jenny's Welcome to Charlie" and the also this untitled reel:
X: 1 T: Gan Ainm R: reel M: 4/4 L: 1/8 N: An untitled reel played by fiddler Kevin Burke after N:Christy Moore sung a song called “Home from N:Barna” on an early recording. F: https://thesession.org/tunes/8104#setting8104 K: Dmix Ad (3ddd dcAB|c2 Bd cAGB|Ad (3ddd dcAB|BcGE ED D2| Ad (3ddd dcAB|cBcd cAGE|DE=FG Addc|(3ABc GE ED D2| D2 AB AGEF|GE (3EEE cABG|D2 AB AGEG|(3ABc GE ED D2| D2 AB AGEF|GE (3EEE c3 d|edcA AGEG|(3ABc GE ED D2|
